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158-4x=x^2+5x
We move all terms to the left:
158-4x-(x^2+5x)=0
We get rid of parentheses
-x^2-4x-5x+158=0
We add all the numbers together, and all the variables
-1x^2-9x+158=0
a = -1; b = -9; c = +158;
Δ = b2-4ac
Δ = -92-4·(-1)·158
Δ = 713
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{713}}{2*-1}=\frac{9-\sqrt{713}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{713}}{2*-1}=\frac{9+\sqrt{713}}{-2} $
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